A typical family in Delhi needs 10 kW of power supply. Direct solar energy is incident on the horizontal surface at an average rate of 200 W per square meter. If 15% of this energy can be converted to useful electrical energy then how much area is required to fulfill the requirement of the family?

117 Physics

08/01/2023

222.22 m²
333.33 m²
444.44 m²
555.55 m²

Answer

333.33 m²

Solution

Required Power = 10 kW = 10,000 W
Power production per square meter = 15 % of Incident Solar Energy = (15*200)/100 = 30 W
Hence, Required Area = 10,000 W/30 W = 333.33 m²

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A typical family in Delhi needs 10 kW of power supply. Direct solar energy is incident on the horizontal surface at an average rate of 200 W per square meter. If 15% of this energy can be converted to useful electrical energy then how much area is required to fulfill the requirement of the family?

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A family uses 8 kW of power. Direct solar energy is incident on the horizontal surface at an average rate of 200 W per square meter. If 20% of this energy can be converted to useful electrical energy, how large an area is needed to to fulfill the requirement of family?

Question 1