**Answer**

200 m

^{2}**Solution**

Required Power = 8 kW = 8,000 W

Power production per square meter = 20 % of Solar Energy Incident = (20*200)/100 = 40 W

Hence, Required Area = 8,000 W/40 W = 200 m

Power production per square meter = 20 % of Solar Energy Incident = (20*200)/100 = 40 W

Hence, Required Area = 8,000 W/40 W = 200 m

^{2}